I had Hunter graph parabolas by first finding the value of x = -b/2a. This value is the axis of symmetry. He then took this value, plugged it into the equation, and found the y value. This ordered pair (x,y), is the vertex of the parabola. He then graphed the y-intercept, c. He did exercises p. 248(11-27, 31, 33, 37-39)